В(l)= -l2-1 l2+2 = -1 1 -1 2 ,

1 1 3 5 l2+4 2l2+13

|Bo| = 1, Bo-1 = 1 2 , А0B0-1 = 2 5 , А0B0-1В(l) = -l2+1 3l2+12 ,

l3+l 2l3+l2 l3+4l 2l3+13l -3l l2-13l

А(1)(l)= -l3-2l2+1 3l3+l - -l3+l 3l3+12l = -2l2-l+1 -11l ,

0 1 l2+ -3 -13 l+ 0 0

А(1)(l)= -2 0 -1 -11 1 0 ,

0 1 × 1 1 1 2

А0(1)В0-1(l)= -2 0 1 2 = -2 -2 ,

1 2 × 2l2+3 -l2+1 = 1 l2+5

А0(1)В0-1В(l)= -2 -2 -l2-1 l2+1 -2l2-4 -6 ,

R(l)= А(1)(l) - А0(1)В0-1В(l)=

-3l l2-13l - 1 l2+5 = -3l-1 -13l -5